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JEE Main & Advanced Physics Elasticity Question Bank Work Done in Stretching a Wire

  • question_answer
    A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm Then the elastic energy stored in the wire is                                  [AIEEE 2003]

    A) 0.1 J   

    B)             0.2 J

    C)             10 J    

    D)             20

    Correct Answer: A

    Solution :

                 \[U=\frac{1}{2}\times F\times l=\frac{1}{2}\times 200\times {{10}^{-3}}=0.1\ J\]


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