A) \[{{E}_{1}}\] is greater than \[{{E}_{2}}\]
B) \[{{E}_{1}}\] is less than \[{{E}_{2}}\]
C) \[{{E}_{1}}\] is equal to \[{{E}_{2}}\]
D) Ratio of \[{{E}_{1}}\] and \[{{E}_{2}}\] is equal to ratio of \[{{M}_{1}}\]and \[{{M}_{2}}\]
Correct Answer: B
Solution :
\[E=\frac{{{p}^{2}}}{2m}\] if p=constant then \[E\propto \frac{1}{M}\] As \[{{M}_{1}}>{{M}_{2}}\therefore {{E}_{1}}<{{E}_{2}}\]You need to login to perform this action.
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