A) \[{{H}_{2}}S\]
B) \[N{{H}_{4}}CNS\]
C) \[{{K}_{4}}Fe{{(CN)}_{6}}\]
D) \[{{K}_{3}}Fe{{\left( CN \right)}_{6}}\]
Correct Answer: D
Solution :
\[3FeC{{l}_{2}}+2{{K}_{3}}[Fe{{(CN)}_{6}}]\to \underset{\,\,\text{blue }\,\text{colour}}{\mathop{F{{e}_{3}}{{[Fe{{(CN)}_{6}}]}_{2}}}}\,+6KCl\]
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