A) \[HI\]
B) \[{{I}_{2}}\]
C) \[HI{{O}_{3}}\]
D) \[KI{{O}_{3}}\]
Correct Answer: B
Solution :
\[2KI+2{{H}_{2}}S{{O}_{4}}\ (\text{Conc}\text{.)}\ \to 2KHS{{O}_{4}}\ +\ 2HI\] \[Mn{{O}_{2}}+{{H}_{2}}S{{O}_{4}}\to MnS{{O}_{4}}+{{H}_{2}}O+(O)\] \[2HI+(O)\to {{H}_{2}}O+{{I}_{2}}\] \[2KI+Mn{{O}_{2}}+3{{H}_{2}}S{{O}_{4}}\to {{I}_{2}}+MnS{{O}_{4}}+2{{H}_{2}}O\]\[+2KHS{{O}_{4}}\]
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