A) 36 : 1
B) 9 : 4
C) 25 : 1
D) 6 : 4
Correct Answer: C
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\frac{{{a}_{1}}}{{{a}_{2}}}+1}{\frac{{{a}_{1}}}{{{a}_{2}}}-1} \right)}^{2}}=\frac{25}{1}\]
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