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JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

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    100 \[c{{m}^{3}}\] of 0.1 N \[HCl\] solution is mixed with 100 \[c{{m}^{3}}\] of 0.2 N \[NaOH\] solution. The resulting solution is [MP PET 1996]

    A) 0.1 N and the solution is basic

    B) 0.05 N and the solution is basic

    C) 0.1 N and the solution is acidic

    D) 0.05 N and the solution is acidic

    Correct Answer: B

    Solution :

    Acid = 0.1 × 100 = 10 Base = 0.2 × 100 = 20   \ solution will be basic. 0.1N of HCl is neutralised by 0.1 N of NaOH and the remaining 0.1N of NaOH is in 200 \[c{{m}^{3}}\]of solution.  \ resulting normality = 0.05 N, basic.


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