JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    0.53 gm of \[N{{a}_{2}}C{{O}_{3}}\] has been dissolved in 100 ml of a sodium carbonate solution. The normality of the solution will be [MP PMT 1996]

    A) \[\frac{N}{5}\]

    B) \[\frac{N}{2}\]

    C) \[\frac{N}{10}\]

    D) \[N\]

    Correct Answer: C

    Solution :

    \[N=\frac{0.53\times 1000}{53\times 100}\Rightarrow N=\frac{1}{10}\] So normality of the solution will be \[\frac{N}{10}\].


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