A) 5.06 km/s
B) 6.06 km/s
C) 7.06 km/s
D) 8.06 km/s
Correct Answer: A
Solution :
If a rod clamped at middle, then it vibrates with similar fashion as open organ pipe vibrates as shown. Hence, fundamental frequency of vibrating rod is given by \[{{n}_{1}}=\frac{v}{2l}\]Þ \[2.53=\frac{v}{4\times 1}\]Þ v = 5.06 km/sec.You need to login to perform this action.
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