A) 20%
B) 30%
C) \[\sqrt{69}%\]
D) 69%
Correct Answer: B
Solution :
\[n\propto \frac{\sqrt{T}}{l}\]\[\Rightarrow l\propto \sqrt{T}\] (As \[n\]= constant) Þ\[\frac{{{l}_{2}}}{{{l}_{1}}}=\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}={{l}_{1}}\sqrt{\frac{169}{100}}\Rightarrow {{l}_{2}}=1.3{{l}_{1}}={{l}_{1}}+30%\] of \[{{l}_{1}}\]You need to login to perform this action.
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