A) \[\frac{3}{8}\]
B) \[\frac{2}{3}\]
C) \[\frac{8}{9}\]
D) \[\frac{9}{4}\]
Correct Answer: D
Solution :
\[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\Rightarrow n\propto \frac{\sqrt{T}}{l}\] Þ \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{n}_{2}}}{{{n}_{1}}} \right)}^{2}}{{\left( \frac{{{l}_{2}}}{{{l}_{1}}} \right)}^{2}}={{(2)}^{2}}{{\left( \frac{3}{4} \right)}^{2}}=\frac{9}{4}\]You need to login to perform this action.
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