A) \[2\pi \,sec\]
B) \[\pi /2\]sec
C) \[\pi \,sec\]
D) \[3\pi /2\,sec\]
Correct Answer: C
Solution :
\[v=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\]Þ\[10=\omega \sqrt{{{a}^{2}}-{{(4)}^{2}}}\]and \[8=\omega \sqrt{{{a}^{2}}-{{(5)}^{2}}}\] On solving w = 2 Þ \[\omega =\frac{2\pi }{T}=2\] Þ \[T=\pi \]sec
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