A) \[\pi \,m/s\]
B) \[\sqrt{2\pi }\,m/s\]
C) \[2\pi \,m/s\]
D) \[4\pi \,m/s\]
Correct Answer: C
Solution :
\[{{v}_{\max }}=\omega a=\frac{2\pi }{T}\times a\]Þ \[{{v}_{\max }}=\frac{2\times \pi \times 2}{2}=2\pi \,\,m/s\]
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