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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Velocity of Simple Harmonic Motion

  • question_answer
    A particle executing simple harmonic motion with amplitude of 0.1 m. At a certain instant when its displacement is 0.02 m, its acceleration is 0.5 m/s2. The maximum velocity of the particle is (in m/s)                                          [MP PET 2003]

    A)            0.01                                          

    B)            0.05

    C)            0.5 

    D)            0.25

    Correct Answer: C

    Solution :

                       Acceleration \[A={{\omega }^{2}}y\]\[\Rightarrow \omega =\sqrt{\frac{A}{y}}=\sqrt{\frac{0.5}{0.02}}=5\]            Maximum velocity \[{{v}_{\max }}=a\omega =0.1\times 5=0.5\]


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