A) \[\frac{\pi }{25}\,m/s\]
B) \[\frac{\pi }{26}\,m/s\]
C) \[{{\tan }^{-1}}\frac{a}{g}\]
D) None of these
Correct Answer: A
Solution :
\[{{v}_{\max }}=a\omega =\frac{a\times 2\pi }{T}=\frac{2\times {{10}^{-3}}\times 2\pi }{0.1}=\frac{\pi }{25}m/s\]
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