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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Velocity of Simple Harmonic Motion

  • question_answer
    If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is                    [AIIMS 1998; MH CET 2000; DPMT 2000]

    A)            0.10 m / s                               

    B)            0.15 m / s

    C)            0.8 m / s                                 

    D)            0.26 m / s

    Correct Answer: B

    Solution :

               \[{{v}_{\max }}=a\omega =a\times \frac{2\pi }{T}=(50\times {{10}^{-3}})\times \frac{2\pi }{2}=0.15\,m/s\]


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