A) \[\frac{\pi A\sqrt{3}}{T}\]
B) \[\frac{\pi A}{T}\]
C) \[\frac{\pi A\sqrt{3}}{2T}\]
D) \[\frac{3{{\pi }^{2}}A}{T}\]
Correct Answer: A
Solution :
Velocity of a particle executing S.H.M. is given by \[v=\omega \sqrt{{{a}^{2}}-{{x}^{2}}}=\frac{2\pi }{T}\sqrt{{{A}^{2}}-\frac{{{A}^{2}}}{4}}=\frac{2\pi }{T}\sqrt{\frac{3{{A}^{2}}}{4}}=\frac{\pi A\sqrt{3}}{T}\].
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