A) [b c a] a
B) [c a b] b
C) [a b c] c
D) [a c b] b
Correct Answer: C
Solution :
\[(\mathbf{b}\times \mathbf{c}\,.\,\mathbf{a})\mathbf{c}-(\mathbf{b}\times \mathbf{c}\,.\,\mathbf{c})\mathbf{a}=[\mathbf{b}\,\mathbf{c}\,\mathbf{a}]\mathbf{c}-\mathbf{0}=[\mathbf{a}\,\mathbf{b}\,\mathbf{c}]\mathbf{c}\].
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