JEE Main & Advanced Mathematics Vector Algebra Question Bank Vector or Cross product of two vectors and its application

  • question_answer
    A force \[\mathbf{F}=2\mathbf{i}+\mathbf{j}-\mathbf{k}\] acts at a point A, whose position vector is \[2\mathbf{i}-\mathbf{j}\]. The moment of F about the origin is                                                                 [Karnataka CET 2000]

    A)                 \[\mathbf{i}+2\mathbf{j}-4\mathbf{k}\]

    B)                 \[\mathbf{i}-2\mathbf{j}-4\mathbf{k}\]

    C)                 \[\mathbf{i}+2\mathbf{j}+4\mathbf{k}\]

    D)                 \[\mathbf{i}-2\mathbf{j}+4\mathbf{k}\]

    Correct Answer: C

    Solution :

               Force \[(\overrightarrow{F})=2\mathbf{i}+\mathbf{j}-\mathbf{k}\] and its position vector \[=2\,\mathbf{i}-\mathbf{j}\]. We know that the position vector of a force about origin \[(\mathbf{r})=(2\mathbf{i}-\mathbf{j})-(0\mathbf{i}+0\mathbf{j}+0\mathbf{k})\] or \[\mathbf{r}=2\,\mathbf{i}-\mathbf{j}\]. Therefore, moment of the force about origin \[=\mathbf{r}\times \overrightarrow{F}=\left| \begin{align}   & \,\mathbf{i}\,\,\,\,\,\,\mathbf{j}\,\,\,\,\,\,\,\mathbf{k} \\  & \,2\,\,-1\,\,\,\,\,0 \\  & \,2\,\,\,\,\,1\,\,\,\,-\,1 \\ \end{align} \right|=\mathbf{i}+2\mathbf{j}+4\mathbf{k}\].


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