A) \[{{C}_{2}}{{H}_{5}}OH/Na\]
B) \[LiAl{{H}_{4}}\]
C) \[{{C}_{2}}{{H}_{5}}Mg{{X}^{-}}\]
D) \[Zn/HCl\]
Correct Answer: A
Solution :
\[\underset{\text{Ethyl}\,\text{butyrate}}{\mathop{{{C}_{3}}{{H}_{7}}COO{{C}_{2}}{{H}_{5}}}}\,\xrightarrow{Na/{{C}_{2}}{{H}_{5}}OH}\underset{\text{Butyl}\,\text{alcohol}}{\mathop{{{C}_{3}}{{H}_{7}}C{{H}_{2}}OH}}\,\]
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