A) \[\frac{20}{204}\]
B) \[\frac{5}{204}\]
C) \[\frac{1}{3}\]
D) None of these
Correct Answer: B
Solution :
3 ball can be drawn in \[{}^{18}{{C}_{3}}\] ways Favourable cases \[={}^{6}{{C}_{3}}\] \[\therefore \] Required probability \[=\frac{{}^{6}{{C}_{3}}}{{}^{18}{{C}_{3}}}=\frac{6\times 5\times 4}{18\times 17\times 16}=\frac{5}{204}\].
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