A) \[\frac{1}{3}\]
B) \[\frac{1}{4}\]
C) \[\frac{5}{12}\]
D) \[\frac{2}{3}\]
Correct Answer: D
Solution :
P(Black or Red) \[=\frac{^{5}{{C}_{1}}+{{\,}^{3}}{{C}_{1}}}{^{12}{{C}_{1}}}=\frac{2}{3}\].
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