A) \[\frac{10}{21}\]
B) \[\frac{8}{63}\]
C) \[\frac{5}{21}\]
D) \[\frac{9}{21}\]
Correct Answer: A
Solution :
Total number of ways \[={}^{9}{{C}_{4}},\] 2 children are chosen in \[{}^{4}{{C}_{2}}\] ways and other 2 persons are chosen in \[{}^{5}{{C}_{2}}\] ways. Hence required probability =\[\frac{{}^{4}{{C}_{2}}\times {}^{5}{{C}_{2}}}{{}^{9}{{C}_{4}}}=\frac{10}{21}.\]
You need to login to perform this action.
You will be redirected in
3 sec
