A) \[\left( \begin{align} & 38 \\ & \,3 \\ \end{align} \right)\]
B) \[\left( \begin{align} & 37 \\ & \,2 \\ \end{align} \right)\]
C) \[\left( _{2}^{37} \right)/\left( _{3}^{38} \right)\]
D) \[\frac{666}{8436}\]
Correct Answer: C
Solution :
Required probability \[=\frac{^{37}{{C}_{2}}}{^{38}{{C}_{3}}}=\frac{\left( \begin{align} & 37 \\ & \text{ }2 \\ \end{align} \right)}{\left( \begin{align} & 38 \\ & \text{ }3 \\ \end{align} \right)}\].
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