JEE Main & Advanced Mathematics Probability Question Bank Use of permutations and combinations in probability

  • question_answer
    Out of 40 consecutive natural numbers, two are chosen at random. Probability that the sum of the numbers is odd, is                    [MP PET 1997; Pb. CET 2000]

    A)            \[\frac{14}{29}\]                     

    B)            \[\frac{20}{39}\]

    C)            \[\frac{1}{2}\]                          

    D)            None of these

    Correct Answer: B

    Solution :

               Required probability \[=\frac{{}^{20}{{C}_{1}}\times {}^{20}{{C}_{1}}}{{}^{40}{{C}_{2}}}=\frac{20\times 20\times 2}{40\times 39}=\frac{20}{39}.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner