A) \[\frac{2}{n}\]
B) \[\frac{1}{n}\]
C) \[\frac{2}{(n-1)\,!}\]
D) None of these
Correct Answer: A
Solution :
Total number of ways \[=n\,\,!\]. Favourable cases \[=2(n-1)\,\,!\] Hence required probability \[=\frac{2(n-1)\,\,!}{n\,\,!}=\frac{2}{n}\].
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