A) 5 km/h
B) \[\frac{25}{4}\] km/h
C) \[\frac{30}{4}\] km/h
D) \[\frac{45}{8}\] km/h
Correct Answer: D
Solution :
A man walks from his home to market with a speed of \[5\ km/h\].Distance\[=2.5\ km\] and time\[=\frac{d}{v}=\frac{2.5}{5}=\frac{1}{2}hr\]. and he returns back with speed of \[7.5\ km/h\] in rest of time of 10 minutes. Distance \[=7.5\times \frac{10}{60}=1.25\ km\] So, Average speed\[\because h=ut+\frac{1}{2}g{{t}^{2}}\] \[=\frac{(2.5+1.25)km}{(40/60)hr}=\frac{45}{8}km/hr\].
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