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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Uniform Circular Motion

  • question_answer
    A 100 kg car is moving with a maximum velocity of 9 m/s across a circular track of radius 30 m.  The maximum force of friction between the road and the car is          [Pb. PMT 2000]

    A)             1000 N

    B)                      706 N

    C)             270 N

    D)             200 N

    Correct Answer: C

    Solution :

                    Maximum force of friction = centripetal force             \[\frac{m{{v}^{2}}}{r}=\frac{100\times {{(9)}^{2}}}{30}=270\,N\] 


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