A) \[6\hat{i}+2\hat{j}-3\hat{k}\]
B) \[-18\hat{i}-13\hat{j}+2\hat{k}\]
C) \[4\hat{i}-13\hat{j}+6\hat{k}\]
D) \[6\hat{i}-2\hat{j}+8\hat{k}\]
Correct Answer: B
Solution :
\[\overrightarrow{v}=\overrightarrow{\omega }\times \overrightarrow{r}=\left| \begin{matrix} {\hat{i}} & {\hat{j}} & {\hat{k}} \\ 3 & -4 & 1 \\ 5 & -6 & 6 \\ \end{matrix} \right|=-18\hat{i}-13\hat{j}+2\hat{k}\]
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