A) 6.28 and 0 mm/s
B) 8.88 and 4.44 mm/s
C) 8.88 and 6.28 mm/s
D) 6.28 and 8.88 mm/s
Correct Answer: D
Solution :
\[v=r\omega =\frac{r\times 2\pi }{T}=\frac{0.06\times 2\pi }{60}=6.28\,mm/s\] Magnitude of change in velocity =\[|\overrightarrow{{{v}_{2}}}-\overrightarrow{{{v}_{1}}}|\] \[=\sqrt{v_{1}^{2}+v_{2}^{2}}=8.88\,mm/s\] \[\left( \text{As }{{v}_{1}}={{v}_{2}}=6.28mm/s \right)\]
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