A) \[\frac{\sqrt{3}}{2}.\]
B) \[{{\tan }^{-1}}\left( \frac{3}{5} \right)\]
C) \[{{\tan }^{-1}}(1)\]
D) \[{{\tan }^{-1}}\left( \frac{1}{5} \right)\]
Correct Answer: D
Solution :
The inclination of person from vertical is given by, \[\tan \theta =\frac{{{v}^{2}}}{rg}=\frac{{{(10)}^{2}}}{50\times 10}=\frac{1}{5}\]\ \[\theta ={{\tan }^{-1}}(1/5)\]
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