JEE Main & Advanced Chemistry Structure of Atom Question Bank Uncertainty principle and Schrodinger wave equation

  • question_answer The uncertainty in momentum of an electron is \[1\times {{10}^{-5}}kg\,m/s\]. The uncertainity in its position will be \[(h=6.63\times {{10}^{-34}}Js)\]              [Pb. CET 2000]

    A)                 \[5.28\times {{10}^{-30}}m\]     

    B)                 \[5.25\times {{10}^{-28}}m\]

    C)                 \[1.05\times {{10}^{-26}}m\]     

    D)                 \[2.715\times {{10}^{-30}}m\]

    Correct Answer: A

    Solution :

               Uncertainity in position \[\Delta x=\frac{h}{4\pi \times \Delta p}\]                                 \[=\frac{6.63\times {{10}^{-34}}}{4\times 3.14\times (1\times {{10}^{-5}})}\]\[=5.28\times {{10}^{-30}}m\].

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