A) \[20\sqrt{3}\]
B) \[15\sqrt{3}\]
C) \[18\sqrt{2}\]
D) \[20\sqrt{2}\]
Correct Answer: A
Solution :
(a): \[\tan {{30}^{{}^\circ }}=\frac{AC}{AD}=\frac{AC}{20}\] \[\frac{1}{\sqrt{3}}=\frac{AC}{20},AC=\frac{20}{\sqrt{3}}\] \[cos{{30}^{{}^\circ }}=\frac{20}{BC}\] \[\frac{\sqrt{3}}{2}=\frac{20}{BC},BC=\frac{40}{\sqrt{3}}\] \[AC+BC=\frac{20}{\sqrt{3}}+\frac{40}{\sqrt{3}}=20\sqrt{3}\]
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