A) 2
B) 5
C) 6
D) 4
Correct Answer: D
Solution :
(d): \[\frac{1}{1+{{\cot }^{2}}\theta }+\frac{4}{1+{{\tan }^{2}}\theta }+3{{\sin }^{2}}\theta \] \[=\frac{1}{\cos e{{c}^{2}}\theta }+\frac{4}{{{\sec }^{2}}\theta }+3{{\sin }^{2}}\theta \] \[={{\sin }^{2}}\theta +4co{{s}^{2}}\theta +3{{\sin }^{2}}\theta \] \[=4\left( {{\sin }^{2}}\theta +co{{s}^{2}}\theta \right)=4\]
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