A) \[{{60}^{{}^\circ }}\]
B) \[{{45}^{{}^\circ }}\]
C) \[{{90}^{{}^\circ }}\]
D) \[{{30}^{{}^\circ }}\]
Correct Answer: D
Solution :
(d): \[AB=\frac{10}{3}-2=\frac{4}{3}\] \[BC=\frac{4}{\sqrt{3}}\] \[\tan \theta =\frac{4}{3}\times \frac{\sqrt{3}}{4}=\frac{1}{\sqrt{3}}\] \[\theta ={{30}^{{}^\circ }}\]
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