10th Class Mathematics Introduction to Trigonometry Question Bank Trigonometry

  • question_answer
    In the given figure, \[\mathbf{PS}=\mathbf{SQ}\], then \[\mathbf{sin}\theta =\]?

    A) \[\frac{4{{Q}^{2}}-3{{p}^{2}}}{p}\]

    B) \[\frac{p}{4{{Q}^{2}}-3{{p}^{2}}}\]

    C) \[\frac{\sqrt{4{{Q}^{2}}-3{{p}^{2}}}}{p}\]

    D) 1

    Correct Answer: B

    Solution :

    (b): Not Available


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