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10th Class Mathematics Introduction to Trigonometry Question Bank Trigonometry

  • question_answer
    Which of the following is equal to \[\sin \theta \cos \theta -\frac{\sin \theta \cos (90{}^\circ -\theta )cos\theta }{\sec (90{}^\circ -\theta )}\]\[-\frac{\cos \theta \sin (90{}^\circ -\theta )sin\theta }{\cos ec(90{}^\circ -\theta )}?\]

    A)  1                                

    B)  0  

    C)  ? 1                              

    D)  ? 2

    Correct Answer: B

    Solution :

    (b): \[\sin \theta \cos \theta -\frac{\sin \theta .\sin \theta \cos \theta }{\cos ec\theta }-\frac{\cos \theta .\cos \theta \sin \theta }{\sec \theta }\] \[=\sin \theta cos\theta -sin\theta cos\theta \left[ {{\sin }^{2}}\theta +{{\cos }^{2}}\theta  \right]\] \[=\sin \theta \cos \theta -\sin \theta \cos \theta =0\]          


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