A) \[\frac{m+n}{m-n}\]
B) \[\frac{m+n}{2\sqrt{m+n}}\]
C) \[\frac{m-n}{m+n}\]
D) \[\frac{m+n}{3\sqrt{m+n}}\]
Correct Answer: C
Solution :
(c) \[AB=\sqrt{{{\left( \frac{m+n}{2\sqrt{mn}} \right)}^{2}}-1}\] \[=\frac{m-n}{2\sqrt{mn}}\] \[\sin \theta =\frac{\frac{m-n}{2\sqrt{mn}}}{\frac{m+n}{2\sqrt{mn}}}\] \[=\frac{m-n}{m+n}\]
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