A) \[\frac{p}{q}\]
B) \[\frac{q}{p}\]
C) pq
D) \[{{p}^{2}}{{q}^{2}}\]
Correct Answer: B
Solution :
(b): \[AB=\sqrt{{{\left( \sqrt{{{p}^{2}}+{{q}^{2}}} \right)}^{2}}}-{{p}^{2}}\] \[={{p}^{2}}+{{q}^{2}}-{{p}^{2}}=\sqrt{{{q}^{2}}}=q\] \[tan\theta =\frac{q}{p}\]
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