A) 0
B) 1/2
C) 1
D) None of these
Correct Answer: B
Solution :
\[\sin {{163}^{o}}\cos {{347}^{o}}+\sin {{73}^{o}}\sin {{167}^{o}}\] \[=\sin ({{180}^{o}}-{{17}^{o}})\cos ({{360}^{o}}-{{13}^{o}})+\cos ({{90}^{o}}-{{17}^{o}})\]\[\sin ({{180}^{o}}-{{13}^{o}})\] \[=\sin {{17}^{o}}\cos {{13}^{o}}+\cos {{17}^{o}}\sin {{13}^{o}}=\sin {{30}^{o}}=1/2\].
You need to login to perform this action.
You will be redirected in
3 sec
