question_answer

In the given figure, \[\angle BAC=\angle ADC,\] then \[CA/CB\] is

A)  \[CB\times CD\]                     

B)  \[C{{A}^{2}}\]       

C)  \[DC/AC\]      

D)         \[C{{D}^{2}}\]      

Correct Answer: C

Solution :

In \[\Delta 's\] ABC and DAC, \[\angle BAC=\angle ADC\](Given) (Common angle)             \[\therefore \]    \[\Delta \,ABC\tilde{\ }\Delta DAC\]             \[\Rightarrow \]            \[\frac{AC}{BC}=\frac{DC}{AC}\]