A) \[QP=5\,\,cm,\,\,\angle P={{60}^{o}}\]
B) \[QP=5\,\,cm,\,\,\angle R={{60}^{o}}\]
C) \[QP=5\,\,cm,\,\,\angle R={{60}^{o}}\]
D) \[QP=5\,\,cm,\,\,\angle Q={{40}^{o}}\]
Correct Answer: D
Solution :
\[\Delta ABC=\Delta PQR\](given) \[\Rightarrow \]\[\angle A=\angle P;\angle B=\angle Q;\angle C=\angle R\] and \[AB=PQ;BC=QR;AC=PR\] Since \[AB=5\,cm.\] \[PQ=5\,cm,\]and \[\angle B=\angle Q={{40}^{o}}.\]
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