A) CD < BD
B) CD>BD
C) CD = BD
D) None of these
Correct Answer: A
Solution :
In \[\Delta \Alpha \Beta C,D\]is any point on side Ac and AB = AC. Now in \[\Delta ABC,AC=AB\] \[\therefore \]\[\angle ABC=\angle ACB\] ?(1) [Angles opposite to equal sides of a\[\Delta \]are equal] And \[\angle ABC=\angle ABD+\angle DBC\] \[\Rightarrow \]\[\angle ABC>\angle DBC\] \[\Rightarrow \]\[\angle ACB>\angle DBC\] [From (1)] \[\Rightarrow \]\[BD>CD\][Side opposite to greater angle is longer] or \[CD>BD\]You need to login to perform this action.
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