A) \[\Delta PDC\]
B) \[\Delta PCD\]
C) \[\Delta CPD\]
D) \[\Delta DPC\]
Correct Answer: A
Solution :
\[\angle CPO=\angle BPA\] (vertically opposite angles) \[CP=BP\] (given) \[PD=PA\] (given) \[\therefore \]\[\Delta PAB\cong \Delta PDC\] (SAS congruency)You need to login to perform this action.
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