A) 1 : 3
B) 1 : 4
C) 5 : 4
D) 4 : 5
Correct Answer: D
Solution :
(d):- In \[\Delta ABC\] AD is the internal angle bisector of \[\angle A\]. Using property of internal angle bisector. \[\frac{BD}{CD}=\frac{AB}{AC}\Rightarrow \frac{CD}{BD}=\frac{AC}{AB}\] \[\Rightarrow \] \[\frac{CD}{BD}\text{+1=}\frac{AC}{AB}\text{+1}\] \[\Rightarrow \frac{CD+BD}{BD}=\frac{AC+AB}{AB}\] \[\Rightarrow \]\[\frac{BC}{BD}=\frac{1+4}{4}\Rightarrow \frac{BD}{BC}=\frac{4}{5}\] \[\therefore \]\[BD:BC=4:5\]You need to login to perform this action.
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