A) \[{{x}^{2}}+{{y}^{2}}=2{{a}^{2}}\]
B) \[{{x}^{2}}-{{y}^{2}}={{a}^{2}}\]
C) \[{{x}^{2}}+{{y}^{2}}+{{a}^{2}}=0\]
D) \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\]
Correct Answer: D
Solution :
We know that \[P{{A}^{2}}+P{{B}^{2}}=A{{B}^{2}}\] \[\Rightarrow \,\,{{(x-a)}^{2}}+{{y}^{2}}+{{(x+a)}^{2}}+{{y}^{2}}={{(2a)}^{2}}\,\] \[\,\Rightarrow \,\,{{x}^{2}}+{{y}^{2}}={{a}^{2}}\].You need to login to perform this action.
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