A) 1200 m
B) 0.33 km
C) 3.33 km
D) 33 km
Correct Answer: C
Solution :
[c] Horizontal displacement of the bomb AB = Horizontal velocity × time available \[AB=\,u\times \sqrt{\frac{2h}{g}}\]\[=600\times \frac{5}{18}\times \sqrt{\frac{2\times 1960}{9.8}}\]\[=3.33\,Km.\]You need to login to perform this action.
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