JEE Main & Advanced Physics Transmission of Heat Question Bank Topic Test - Transmission of Heat (3-5-21)

  • question_answer
    In Newton's experiment of cooling, the water equivalent of two similar calorimeters is 10 gm each. They are filled with 350 gm of water and 300 gm of a liquid (equal volumes) separately. The time taken by water and liquid to cool from \[{{70}^{o}}C\] to \[{{60}^{o}}C\] is 3 min and 95 sec respectively. The specific heat of the liquid will be

    A) \[0.3\,Cal\text{/}gm\times {}^\circ C\]

    B) \[0.6\,Cal\text{/}gm\times {}^\circ C\]

    C) \[0.6\,Cal\text{/}gm\times {}^\circ C\]

    D) \[0.8\,Cal\text{/}gm\times {}^\circ C\]

    Correct Answer: C

    Solution :

    \[{{S}_{l}}=\frac{1}{{{m}_{l}}}\left[ \frac{{{t}_{l}}}{{{t}_{W}}}({{m}_{W}}{{C}_{W}}+W)-W \right]\] \[=\frac{1}{300}\left[ \frac{95}{3\times 60}(350\times 1+10)-10 \right]\] \[=0.6\,Cal\text{/}gm\times {}^\circ C\]

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