A) \[-\,2\times {{10}^{-\,3}}\]
B) \[-\,1\times {{10}^{-\,3}}\]
C) \[2\times {{10}^{-\,3}}\]
D) \[1\times {{10}^{-\,3}}\]
Correct Answer: D
Solution :
Fractional change in period \[\frac{\Delta T}{T}=\frac{1}{2}\alpha \,\Delta \theta =\frac{1}{2}\times 2\times {{10}^{-6}}\times 10={{10}^{-5}}\] % change\[=\frac{\Delta T}{T}\times 100={{10}^{-5}}\times 100={{10}^{-3}}\,%\]
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