JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Topic Test - Thermometry, Thermal Expansion and Calorimetry (3-5-21)

  • question_answer
    A constant pressure air thermometer gave a reading of 47.5 units of volume when immersed in ice cold water, and 67 units in a boiling liquids. The boiling point of the liquid will be

    A) \[135{}^\circ C\]

    B) \[125{}^\circ C\]

    C) \[112{}^\circ C\]

    D) \[100{}^\circ C\]

    Correct Answer: C

    Solution :

                  
    Initial volume \[{{V}_{1}}=47.5\] units
    Temperature of ice cold water \[{{T}_{1}}=0{}^\circ C=273\,K\]
    Final volume of \[{{V}_{2}}=67\] units
    Applying Charle’s law, we have \[\frac{{{V}_{1}}}{{{T}_{1}}}=\frac{{{V}_{2}}}{{{T}_{2}}}\]
    (where temperature \[{{T}_{2}}\] is the boiling point)
    or \[{{T}_{2}}=\frac{{{V}_{2}}}{{{V}_{1}}}\times {{T}_{1}}=\frac{67\times 273}{47.5}=385\,K=112{}^\circ C\]


You need to login to perform this action.
You will be redirected in 3 sec spinner