2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Thermodynamical Processes

JEE Main & Advanced Physics Thermodynamical Processes Question Bank Topic Test - Thermodynamical Process (2021)

  • question_answer
    540 calories of heat convert 1 cubic centimeter of water at \[{{100}^{o}}C\] into 1671 cubic centimeter of steam at \[{{100}^{o}}C\] at a pressure of one atmosphere. Then the work done against the atmospheric pressure is nearly

    A) 540 cal

    B) 40 cal

    C) Zero cal

    D) 500 cal

    Correct Answer: B

    Solution :

    [b] Amount of heat given \[=540\ calories\]
    Change in volume \[\Delta V=1670\ c.c\]
    Atmospheric pressure \[P=1.01\times {{10}^{6}}\ dyne/c{{m}^{2}}\]
    Work done against atmospheric pressure
    \[W=P\Delta V\]\[=\frac{1.01\times {{10}^{6}}\times 1670}{4.2\times {{10}^{7}}}\approx 40\ cal\]


You need to login to perform this action.
You will be redirected in 3 sec spinner